Starter
Free
$0/month
- 3 prompt runs per day
- Basic reasoning traces
- Community support
</>CODEWARS
Research model / 001
Make hard problems feel smaller.
A focused workspace for training CodeWars to solve programming problems, explain the path, and leave behind code you can actually inspect.
Pricing
Start free. Upgrade when you need more.
Popular
Pro
$19.99/month
- Unlimited local prompts
- Claude cost estimate tools
- PayPal checkout demo
Scale
Team
$49.99/month
- Shared workspace access
- Premium model routing
- Priority onboarding
1
Claude pricing
Estimate token cost for requests across model tiers before you send a production prompt.
2
PayPal checkout
Use a seamless subscription flow for Pro or Team access with a demo order payload.
3
Active access
Unlock premium workspace features and keep the model, pricing, and billing flow connected.
Problem solver
CodeWars / local demo
Give me a problem. I will break it into an idea, a proof sketch, and an implementation.
You
Find the first non-repeating character in a string.
CodeWars / draft
Count each character once, then scan the string again. The second pass preserves order and finds the first count of one.
def first_unique(text):
counts = {}
for char in text:
counts[char] = counts.get(char, 0) + 1
return next((char for char in text if counts[char] == 1), None)